What are the solutions to the equation (7+2x)(3+2x)=77 ?

The solutions to the equation (7+2x)(3+2x)=77 are x=2,x=-7

Find the zeros of (7+2x)(3+2x)=77

The zeros of (7+2x)(3+2x)=77 are x=2,x=-7

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(7 + 2 x) (3 + 2 x) = 77

x = 2, x = - 7

Solution steps

(7 + 2 x) (3 + 2 x) = 77

Expand

(7 + 2 x) (3 + 2 x) : 21 + 20 x + 4 x^{2}

21 + 20 x + 4 x^{2} = 77

Move

77

to the left side

4 x^{2} + 20 x - 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 ( - 56 )}{2 \cdot 4}

2 0^{2} - 4 \cdot 4 (- 56) = 36

x_{1, 2} = \frac{- 20 \pm 36}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 20 + 36}{2 \cdot 4}, x_{2} = \frac{- 20 - 36}{2 \cdot 4}

x = \frac{- 20 + 36}{2 \cdot 4} : 2

x = \frac{- 20 - 36}{2 \cdot 4} : - 7

The solutions to the quadratic equation are:

x = 2, x = - 7

(3 x + 4)^{2} = 16 (3 x + 4)

x^{2} = 15 x - 36

x, f (x + 2) = 3 x^{2} + 2

y, x - y^{2} = 4

x^{2} - 4 x + 130 = 14 x

What are the solutions to the equation (7+2x)(3+2x)=77 ?
The solutions to the equation (7+2x)(3+2x)=77 are x=2,x=-7
Find the zeros of (7+2x)(3+2x)=77
The zeros of (7+2x)(3+2x)=77 are x=2,x=-7