What are the solutions to the equation 3x^2+1=121 ?

The solutions to the equation 3x^2+1=121 are x=2sqrt(10),x=-2sqrt(10)

Find the zeros of 3x^2+1=121

The zeros of 3x^2+1=121 are x=2sqrt(10),x=-2sqrt(10)

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3 x^{2} + 1 = 121

x = 210, x = - 210

Decimal Notation

x = 6.32455 \dots, x = - 6.32455 \dots

Solution steps

3 x^{2} + 1 = 121

Move

1

to the right side

3 x^{2} = 120

Divide both sides by

3

x^{2} = 40

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 40, x = - 40

40 = 210

- 40 = - 210

x = 210, x = - 210

x^{2} + 8 x - 84 = 0

(z + 1)^{2} + 2 = 0

(x - 2)^{2} = 4 - 9 x

A = 5 x (3 x + 2)

- 7 x^{2} + 4 x + \frac{2}{5} = 0

What are the solutions to the equation 3x^2+1=121 ?
The solutions to the equation 3x^2+1=121 are x=2sqrt(10),x=-2sqrt(10)
Find the zeros of 3x^2+1=121
The zeros of 3x^2+1=121 are x=2sqrt(10),x=-2sqrt(10)