What are the solutions to the equation 100+60L-12L^2=0 ?

The solutions to the equation 100+60L-12L^2=0 are L=-(5(sqrt(21)-3))/6 ,L=(5(3+sqrt(21)))/6

Find the zeros of 100+60L-12L^2=0

The zeros of 100+60L-12L^2=0 are L=-(5(sqrt(21)-3))/6 ,L=(5(3+sqrt(21)))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

100 + 60 L - 12 L^{2} = 0

L = - \frac{5 ( 21 - 3 )}{6}, L = \frac{5 ( 3 + 21 )}{6}

Decimal Notation

L = - 1.31881 \dots, L = 6.31881 \dots

Solution steps

100 + 60 L - 12 L^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 12 L^{2} + 60 L + 100 = 0

Solve with the quadratic formula

L_{1, 2} = \frac{- 60 \pm 6 0 ^{2} - 4 ( - 12 ) \cdot 100}{2 ( - 12 )}

6 0^{2} - 4 (- 12) \cdot 100 = 2021

L_{1, 2} = \frac{- 60 \pm 20 21}{2 ( - 12 )}

Separate the solutions

L_{1} = \frac{- 60 + 20 21}{2 ( - 12 )}, L_{2} = \frac{- 60 - 20 21}{2 ( - 12 )}

L = \frac{- 60 + 20 21}{2 ( - 12 )} : - \frac{5 ( 21 - 3 )}{6}

L = \frac{- 60 - 20 21}{2 ( - 12 )} : \frac{5 ( 3 + 21 )}{6}

The solutions to the quadratic equation are:

L = - \frac{5 ( 21 - 3 )}{6}, L = \frac{5 ( 3 + 21 )}{6}

(x + 9)^{2} = 256

y^{2} = 256

2 x^{2} + 6 x - 27 = 0

2 x^{2} = 10 x + 28

5 x^{2} = 160

What are the solutions to the equation 100+60L-12L^2=0 ?
The solutions to the equation 100+60L-12L^2=0 are L=-(5(sqrt(21)-3))/6 ,L=(5(3+sqrt(21)))/6
Find the zeros of 100+60L-12L^2=0
The zeros of 100+60L-12L^2=0 are L=-(5(sqrt(21)-3))/6 ,L=(5(3+sqrt(21)))/6