What are the solutions to the equation 2x^2+6x-27=0 ?

The solutions to the equation 2x^2+6x-27=0 are x=(3(sqrt(7)-1))/2 ,x=-(3(1+sqrt(7)))/2

Find the zeros of 2x^2+6x-27=0

The zeros of 2x^2+6x-27=0 are x=(3(sqrt(7)-1))/2 ,x=-(3(1+sqrt(7)))/2

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2 x^{2} + 6 x - 27 = 0

x = \frac{3 ( 7 - 1 )}{2}, x = - \frac{3 ( 1 + 7 )}{2}

Decimal Notation

x = 2.46862 \dots, x = - 5.46862 \dots

Solution steps

2 x^{2} + 6 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 ( - 27 )}{2 \cdot 2}

6^{2} - 4 \cdot 2 (- 27) = 67

x_{1, 2} = \frac{- 6 \pm 6 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 6 + 6 7}{2 \cdot 2}, x_{2} = \frac{- 6 - 6 7}{2 \cdot 2}

x = \frac{- 6 + 6 7}{2 \cdot 2} : \frac{3 ( 7 - 1 )}{2}

x = \frac{- 6 - 6 7}{2 \cdot 2} : - \frac{3 ( 1 + 7 )}{2}

The solutions to the quadratic equation are:

x = \frac{3 ( 7 - 1 )}{2}, x = - \frac{3 ( 1 + 7 )}{2}

2 x^{2} = 10 x + 28

5 x^{2} = 160

(3 + 2 x) (x - 7) = 0

(2 x - 3.8) (4.2 + 3 x) = 0

(f + 7) (f + 3) = 21

What are the solutions to the equation 2x^2+6x-27=0 ?
The solutions to the equation 2x^2+6x-27=0 are x=(3(sqrt(7)-1))/2 ,x=-(3(1+sqrt(7)))/2
Find the zeros of 2x^2+6x-27=0
The zeros of 2x^2+6x-27=0 are x=(3(sqrt(7)-1))/2 ,x=-(3(1+sqrt(7)))/2