What are the solutions to the equation (3+2x)(x-7)=0 ?

The solutions to the equation (3+2x)(x-7)=0 are x=-3/2 ,x=7

Find the zeros of (3+2x)(x-7)=0

The zeros of (3+2x)(x-7)=0 are x=-3/2 ,x=7

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(3 + 2 x) (x - 7) = 0

x = - \frac{3}{2}, x = 7

Decimal Notation

x = - 1.5, x = 7

Solution steps

(3 + 2 x) (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 + 2 x = 0 or x - 7 = 0

Solve

3 + 2 x = 0 : x = - \frac{3}{2}

Solve

x - 7 = 0 : x = 7

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = 7

(2 x - 3.8) (4.2 + 3 x) = 0

(f + 7) (f + 3) = 21

3 x (4 - x) = 0

x^{2} + 63 = 16 x

(a - 2) (a + 3) = 0

What are the solutions to the equation (3+2x)(x-7)=0 ?
The solutions to the equation (3+2x)(x-7)=0 are x=-3/2 ,x=7
Find the zeros of (3+2x)(x-7)=0
The zeros of (3+2x)(x-7)=0 are x=-3/2 ,x=7