What are the solutions to the equation (2x-3.8)(4.2+3x)=0 ?

The solutions to the equation (2x-3.8)(4.2+3x)=0 are x=1.9,x=-1.4

Find the zeros of (2x-3.8)(4.2+3x)=0

The zeros of (2x-3.8)(4.2+3x)=0 are x=1.9,x=-1.4

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(2 x - 3.8) (4.2 + 3 x) = 0

x = 1.9, x = - 1.4

Solution steps

(2 x - 3.8) (4.2 + 3 x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 3.8 = 0 or 4.2 + 3 x = 0

Solve

2 x - 3.8 = 0 : x = 1.9

Solve

4.2 + 3 x = 0 : x = - 1.4

The solutions to the quadratic equation are:

x = 1.9, x = - 1.4

(f + 7) (f + 3) = 21

3 x (4 - x) = 0

x^{2} + 63 = 16 x

(a - 2) (a + 3) = 0

(4 x + 5)^{2} = 7

What are the solutions to the equation (2x-3.8)(4.2+3x)=0 ?
The solutions to the equation (2x-3.8)(4.2+3x)=0 are x=1.9,x=-1.4
Find the zeros of (2x-3.8)(4.2+3x)=0
The zeros of (2x-3.8)(4.2+3x)=0 are x=1.9,x=-1.4