What are the solutions to the equation (4x+5)^2=7 ?

The solutions to the equation (4x+5)^2=7 are x=(sqrt(7)-5)/4 ,x=(-sqrt(7)-5)/4

Find the zeros of (4x+5)^2=7

The zeros of (4x+5)^2=7 are x=(sqrt(7)-5)/4 ,x=(-sqrt(7)-5)/4

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(4 x + 5)^{2} = 7

x = \frac{7 - 5}{4}, x = \frac{- 7 - 5}{4}

Decimal Notation

x = - 0.58856 \dots, x = - 1.91143 \dots

Solution steps

(4 x + 5)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x + 5 = 7 : x = \frac{7 - 5}{4}

Solve

4 x + 5 = - 7 : x = \frac{- 7 - 5}{4}

The solutions to the quadratic equation are:

x = \frac{7 - 5}{4}, x = \frac{- 7 - 5}{4}

- 3 x^{2} + 7 x + 3 = 0

y (4 - y) = 0

\frac{1}{4} x^{2} = 2 x^{2}

a^{2} - a + \frac{1}{4} = 0

x^{2} - 7 x + \frac{49}{4} = 0

What are the solutions to the equation (4x+5)^2=7 ?
The solutions to the equation (4x+5)^2=7 are x=(sqrt(7)-5)/4 ,x=(-sqrt(7)-5)/4
Find the zeros of (4x+5)^2=7
The zeros of (4x+5)^2=7 are x=(sqrt(7)-5)/4 ,x=(-sqrt(7)-5)/4