What are the solutions to the equation 3x^2-2x=x^2+4 ?

The solutions to the equation 3x^2-2x=x^2+4 are x=2,x=-1

Find the zeros of 3x^2-2x=x^2+4

The zeros of 3x^2-2x=x^2+4 are x=2,x=-1

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3 x^{2} - 2 x = x^{2} + 4

x = 2, x = - 1

Solution steps

3 x^{2} - 2 x = x^{2} + 4

Move

4

to the left side

3 x^{2} - 2 x - 4 = x^{2}

Move

x^{2}

to the left side

2 x^{2} - 2 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

(- 2)^{2} - 4 \cdot 2 (- 4) = 6

x_{1, 2} = \frac{- ( - 2 ) \pm 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 6}{2 \cdot 2}, x_{2} = \frac{- ( - 2 ) - 6}{2 \cdot 2}

x = \frac{- ( - 2 ) + 6}{2 \cdot 2} : 2

x = \frac{- ( - 2 ) - 6}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = 2, x = - 1

2 x^{2} + 6 x = - 8

- x^{2} + 6 x + 7

(- \frac{5}{13})^{2} + y^{2} = 1

- x^{2} + 6 x - 7

x^{2} - 37 = 0

What are the solutions to the equation 3x^2-2x=x^2+4 ?
The solutions to the equation 3x^2-2x=x^2+4 are x=2,x=-1
Find the zeros of 3x^2-2x=x^2+4
The zeros of 3x^2-2x=x^2+4 are x=2,x=-1