What are the solutions to the equation z^2+256=0 ?

The solutions to the equation z^2+256=0 are z=16i,z=-16i

Find the zeros of z^2+256=0

The zeros of z^2+256=0 are z=16i,z=-16i

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z^{2} + 256 = 0

z = 16 i, z = - 16 i

Solution steps

z^{2} + 256 = 0

Move

256

to the right side

z^{2} = - 256

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = - 256, z = - - 256

- 256 = 16 i

- - 256 = - 16 i

z = 16 i, z = - 16 i

b^{2} + b - 6 = 0

2 x^{2} - 20 x + 50 = 32

4 y^{2} - 80 = 0

19 = - 16 t^{2} + 32 t + 3

(x - 12)^{2} = 12

What are the solutions to the equation z^2+256=0 ?
The solutions to the equation z^2+256=0 are z=16i,z=-16i
Find the zeros of z^2+256=0
The zeros of z^2+256=0 are z=16i,z=-16i