What are the solutions to the equation 19=-16t^2+32t+3 ?

The solutions to the equation 19=-16t^2+32t+3 are t=1

Find the zeros of 19=-16t^2+32t+3

The zeros of 19=-16t^2+32t+3 are t=1

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19 = - 16 t^{2} + 32 t + 3

t = 1

Solution steps

19 = - 16 t^{2} + 32 t + 3

Switch sides

- 16 t^{2} + 32 t + 3 = 19

Move

19

to the left side

- 16 t^{2} + 32 t - 16 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 ( - 16 ) ( - 16 )}{2 ( - 16 )}

3 2^{2} - 4 (- 16) (- 16) = 0

t_{1, 2} = \frac{- 32 \pm 0}{2 ( - 16 )}

t = \frac{- 32}{2 ( - 16 )}

\frac{- 32}{2 ( - 16 )} = 1

t = 1

The solution to the quadratic equation is:

t = 1

(x - 12)^{2} = 12

3 x^{2} - 5 x = 12

a^{2} - 8 a + 7 = 0

4 x^{2} = - 10 x + 7

x, x^{2} - x y = 4

What are the solutions to the equation 19=-16t^2+32t+3 ?
The solutions to the equation 19=-16t^2+32t+3 are t=1
Find the zeros of 19=-16t^2+32t+3
The zeros of 19=-16t^2+32t+3 are t=1