What are the solutions to the equation a^2-8a+7=0 ?

The solutions to the equation a^2-8a+7=0 are a=7,a=1

Find the zeros of a^2-8a+7=0

The zeros of a^2-8a+7=0 are a=7,a=1

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a^{2} - 8 a + 7 = 0

a = 7, a = 1

Solution steps

a^{2} - 8 a + 7 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 7 = 6

a_{1, 2} = \frac{- ( - 8 ) \pm 6}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 8 ) + 6}{2 \cdot 1}, a_{2} = \frac{- ( - 8 ) - 6}{2 \cdot 1}

a = \frac{- ( - 8 ) + 6}{2 \cdot 1} : 7

a = \frac{- ( - 8 ) - 6}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

a = 7, a = 1

4 x^{2} = - 10 x + 7

x, x^{2} - x y = 4

- 2 + 4 k^{2} = - 15

- (2 x^{2} + 7) = (2 x + 1) (x + 3)

0 = 4 x^{2} + 8 x + 4

What are the solutions to the equation a^2-8a+7=0 ?
The solutions to the equation a^2-8a+7=0 are a=7,a=1
Find the zeros of a^2-8a+7=0
The zeros of a^2-8a+7=0 are a=7,a=1