What are the solutions to the equation x(3x+1)=x^2+15 ?

The solutions to the equation x(3x+1)=x^2+15 are x= 5/2 ,x=-3

Find the zeros of x(3x+1)=x^2+15

The zeros of x(3x+1)=x^2+15 are x= 5/2 ,x=-3

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x (3 x + 1) = x^{2} + 15

x = \frac{5}{2}, x = - 3

Decimal Notation

x = 2.5, x = - 3

Solution steps

x (3 x + 1) = x^{2} + 15

Expand

x (3 x + 1) : 3 x^{2} + x

3 x^{2} + x = x^{2} + 15

Move

15

to the left side

3 x^{2} + x - 15 = x^{2}

Move

x^{2}

to the left side

2 x^{2} + x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 15) = 11

x_{1, 2} = \frac{- 1 \pm 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 11}{2 \cdot 2}, x_{2} = \frac{- 1 - 11}{2 \cdot 2}

x = \frac{- 1 + 11}{2 \cdot 2} : \frac{5}{2}

x = \frac{- 1 - 11}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - 3

(4 x + 9) (5 x - 7) = 0

0 = 3 (x - 2)^{2}

4 x^{2} = 31 x + 8

x^{2} - 1 x - 12 = 0

x, 2 = 3 x^{2} - 4 y^{3}

What are the solutions to the equation x(3x+1)=x^2+15 ?
The solutions to the equation x(3x+1)=x^2+15 are x= 5/2 ,x=-3
Find the zeros of x(3x+1)=x^2+15
The zeros of x(3x+1)=x^2+15 are x= 5/2 ,x=-3