What are the solutions to the equation 400-x^2=60x-300 ?

The solutions to the equation 400-x^2=60x-300 are x=-70,x=10

Find the zeros of 400-x^2=60x-300

The zeros of 400-x^2=60x-300 are x=-70,x=10

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400 - x^{2} = 60 x - 300

x = - 70, x = 10

Solution steps

400 - x^{2} = 60 x - 300

Move

300

to the left side

- x^{2} + 700 = 60 x

Move

60 x

to the left side

- x^{2} + 700 - 60 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} - 60 x + 700 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 60 ) \pm ( - 60 ) ^{2} - 4 ( - 1 ) \cdot 700}{2 ( - 1 )}

(- 60)^{2} - 4 (- 1) \cdot 700 = 80

x_{1, 2} = \frac{- ( - 60 ) \pm 80}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 60 ) + 80}{2 ( - 1 )}, x_{2} = \frac{- ( - 60 ) - 80}{2 ( - 1 )}

x = \frac{- ( - 60 ) + 80}{2 ( - 1 )} : - 70

x = \frac{- ( - 60 ) - 80}{2 ( - 1 )} : 10

The solutions to the quadratic equation are:

x = - 70, x = 10

3 x^{2} + 11 x = - 5

x, x^{2} + x y + y^{2} - 3 = 0

d^{2} + 8 d + 12 = 0

12 x^{2} + 17 x = 7

2 x^{2} - 5 x - 2 = 0

What are the solutions to the equation 400-x^2=60x-300 ?
The solutions to the equation 400-x^2=60x-300 are x=-70,x=10
Find the zeros of 400-x^2=60x-300
The zeros of 400-x^2=60x-300 are x=-70,x=10