What are the solutions to the equation 7^2=b^2+b^2 ?

The solutions to the equation 7^2=b^2+b^2 are b= 7/(sqrt(2)),b=-7/(sqrt(2))

Find the zeros of 7^2=b^2+b^2

The zeros of 7^2=b^2+b^2 are b= 7/(sqrt(2)),b=-7/(sqrt(2))

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7^{2} = b^{2} + b^{2}

b = \frac{7}{2}, b = - \frac{7}{2}

Decimal Notation

b = 4.94974 \dots, b = - 4.94974 \dots

Solution steps

7^{2} = b^{2} + b^{2}

Switch sides

b^{2} + b^{2} = 7^{2}

Add similar elements:

b^{2} + b^{2} = 2 b^{2}

2 b^{2} = 7^{2}

7^{2} = 49

2 b^{2} = 49

Divide both sides by

2

b^{2} = \frac{49}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = \frac{49}{2}, b = - \frac{49}{2}

\frac{49}{2} = \frac{7}{2}

- \frac{49}{2} = - \frac{7}{2}

b = \frac{7}{2}, b = - \frac{7}{2}

(x - 9)^{2} + 18 = 0

4 x^{2} - 32 x + 244 = 0

2 x^{2} + 10 x + 13

- 7 x^{2} + 63 = 7

9 x^{2} - 1 = 0

What are the solutions to the equation 7^2=b^2+b^2 ?
The solutions to the equation 7^2=b^2+b^2 are b= 7/(sqrt(2)),b=-7/(sqrt(2))
Find the zeros of 7^2=b^2+b^2
The zeros of 7^2=b^2+b^2 are b= 7/(sqrt(2)),b=-7/(sqrt(2))