What are the solutions to the equation -7x^2+63=7 ?

The solutions to the equation -7x^2+63=7 are x=2sqrt(2),x=-2sqrt(2)

Find the zeros of -7x^2+63=7

The zeros of -7x^2+63=7 are x=2sqrt(2),x=-2sqrt(2)

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- 7 x^{2} + 63 = 7

x = 22, x = - 22

Decimal Notation

x = 2.82842 \dots, x = - 2.82842 \dots

Solution steps

- 7 x^{2} + 63 = 7

Move

63

to the right side

- 7 x^{2} = - 56

Divide both sides by

- 7

x^{2} = 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 8, x = - 8

8 = 22

- 8 = - 22

x = 22, x = - 22

9 x^{2} - 1 = 0

x, f (x + 2) = 3 x^{2} + 5 x - 2

(x - 7)^{2} + 3 (x + 8) = 2

8 x^{2} - 4 x - 4 = 0

r, 2 π r^{2} + 2 π r h = A

What are the solutions to the equation -7x^2+63=7 ?
The solutions to the equation -7x^2+63=7 are x=2sqrt(2),x=-2sqrt(2)
Find the zeros of -7x^2+63=7
The zeros of -7x^2+63=7 are x=2sqrt(2),x=-2sqrt(2)