What are the solutions to the equation -x^2+7x+4=0 ?

The solutions to the equation -x^2+7x+4=0 are x=-(-7+sqrt(65))/2 ,x=(7+sqrt(65))/2

Find the zeros of -x^2+7x+4=0

The zeros of -x^2+7x+4=0 are x=-(-7+sqrt(65))/2 ,x=(7+sqrt(65))/2

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- x^{2} + 7 x + 4 = 0

x = - \frac{- 7 + 65}{2}, x = \frac{7 + 65}{2}

Decimal Notation

x = - 0.53112 \dots, x = 7.53112 \dots

Solution steps

- x^{2} + 7 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 1 ) \cdot 4}{2 ( - 1 )}

7^{2} - 4 (- 1) \cdot 4 = 65

x_{1, 2} = \frac{- 7 \pm 65}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 7 + 65}{2 ( - 1 )}, x_{2} = \frac{- 7 - 65}{2 ( - 1 )}

x = \frac{- 7 + 65}{2 ( - 1 )} : - \frac{- 7 + 65}{2}

x = \frac{- 7 - 65}{2 ( - 1 )} : \frac{7 + 65}{2}

The solutions to the quadratic equation are:

x = - \frac{- 7 + 65}{2}, x = \frac{7 + 65}{2}

49 x^{2} + 9 = 0

8 x^{2} + 16 x + 6 = 0

4 x^{2} + 8 x + 2

27 - 6 Q^{2} = 0

- 2 y^{2} = 8 - 8 y

What are the solutions to the equation -x^2+7x+4=0 ?
The solutions to the equation -x^2+7x+4=0 are x=-(-7+sqrt(65))/2 ,x=(7+sqrt(65))/2
Find the zeros of -x^2+7x+4=0
The zeros of -x^2+7x+4=0 are x=-(-7+sqrt(65))/2 ,x=(7+sqrt(65))/2