What are the solutions to the equation 3v^2+11v+9=0 ?

The solutions to the equation 3v^2+11v+9=0 are v=(-11+sqrt(13))/6 ,v=(-11-sqrt(13))/6

Find the zeros of 3v^2+11v+9=0

The zeros of 3v^2+11v+9=0 are v=(-11+sqrt(13))/6 ,v=(-11-sqrt(13))/6

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3 v^{2} + 11 v + 9 = 0

v = \frac{- 11 + 13}{6}, v = \frac{- 11 - 13}{6}

Decimal Notation

v = - 1.23240 \dots, v = - 2.43425 \dots

Solution steps

3 v^{2} + 11 v + 9 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 3 \cdot 9}{2 \cdot 3}

1 1^{2} - 4 \cdot 3 \cdot 9 = 13

v_{1, 2} = \frac{- 11 \pm 13}{2 \cdot 3}

Separate the solutions

v_{1} = \frac{- 11 + 13}{2 \cdot 3}, v_{2} = \frac{- 11 - 13}{2 \cdot 3}

v = \frac{- 11 + 13}{2 \cdot 3} : \frac{- 11 + 13}{6}

v = \frac{- 11 - 13}{2 \cdot 3} : \frac{- 11 - 13}{6}

The solutions to the quadratic equation are:

v = \frac{- 11 + 13}{6}, v = \frac{- 11 - 13}{6}

2 = x (x + 2)

2 x (x - 2) = 5 x^{2} - 5 x

(3 a + 12) (3 a - 12) = 0

- (x - 2)^{2} - 15 = - 33

x^{2} + 4 x - 3 = 2 x

What are the solutions to the equation 3v^2+11v+9=0 ?
The solutions to the equation 3v^2+11v+9=0 are v=(-11+sqrt(13))/6 ,v=(-11-sqrt(13))/6
Find the zeros of 3v^2+11v+9=0
The zeros of 3v^2+11v+9=0 are v=(-11+sqrt(13))/6 ,v=(-11-sqrt(13))/6