What are the solutions to the equation -2x^2+4x+194=0 ?

The solutions to the equation -2x^2+4x+194=0 are x=1-7sqrt(2),x=1+7sqrt(2)

Find the zeros of -2x^2+4x+194=0

The zeros of -2x^2+4x+194=0 are x=1-7sqrt(2),x=1+7sqrt(2)

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- 2 x^{2} + 4 x + 194 = 0

x = 1 - 72, x = 1 + 72

Decimal Notation

x = - 8.89949 \dots, x = 10.89949 \dots

Solution steps

- 2 x^{2} + 4 x + 194 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 2 ) \cdot 194}{2 ( - 2 )}

4^{2} - 4 (- 2) \cdot 194 = 282

x_{1, 2} = \frac{- 4 \pm 28 2}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 4 + 28 2}{2 ( - 2 )}, x_{2} = \frac{- 4 - 28 2}{2 ( - 2 )}

x = \frac{- 4 + 28 2}{2 ( - 2 )} : 1 - 72

x = \frac{- 4 - 28 2}{2 ( - 2 )} : 1 + 72

The solutions to the quadratic equation are:

x = 1 - 72, x = 1 + 72

9 x^{2} + 6 = - 21 x

0 = x^{2} - 64

r^{2} + 4 r = 12

a, c = ab + a^{2}

27 x^{2} - \frac{11}{8} x + 5 = 0

What are the solutions to the equation -2x^2+4x+194=0 ?
The solutions to the equation -2x^2+4x+194=0 are x=1-7sqrt(2),x=1+7sqrt(2)
Find the zeros of -2x^2+4x+194=0
The zeros of -2x^2+4x+194=0 are x=1-7sqrt(2),x=1+7sqrt(2)