What are the solutions to the equation 9x^2+6=-21x ?

The solutions to the equation 9x^2+6=-21x are x=-1/3 ,x=-2

Find the zeros of 9x^2+6=-21x

The zeros of 9x^2+6=-21x are x=-1/3 ,x=-2

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9 x^{2} + 6 = - 21 x

x = - \frac{1}{3}, x = - 2

Decimal Notation

x = - 0.33333 \dots, x = - 2

Solution steps

9 x^{2} + 6 = - 21 x

Move

21 x

to the left side

9 x^{2} + 6 + 21 x = 0

Write in the standard form

a x^{2} + b x + c = 0

9 x^{2} + 21 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 9 \cdot 6}{2 \cdot 9}

2 1^{2} - 4 \cdot 9 \cdot 6 = 15

x_{1, 2} = \frac{- 21 \pm 15}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 21 + 15}{2 \cdot 9}, x_{2} = \frac{- 21 - 15}{2 \cdot 9}

x = \frac{- 21 + 15}{2 \cdot 9} : - \frac{1}{3}

x = \frac{- 21 - 15}{2 \cdot 9} : - 2

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - 2

0 = x^{2} - 64

r^{2} + 4 r = 12

a, c = ab + a^{2}

27 x^{2} - \frac{11}{8} x + 5 = 0

(x + 4) (x - 2) = 4 x

What are the solutions to the equation 9x^2+6=-21x ?
The solutions to the equation 9x^2+6=-21x are x=-1/3 ,x=-2
Find the zeros of 9x^2+6=-21x
The zeros of 9x^2+6=-21x are x=-1/3 ,x=-2