What are the solutions to the equation factor (x+4)(x-2)=4x ?

The solutions to the equation factor (x+4)(x-2)=4x are x=-2,x=4

Find the zeros of factor (x+4)(x-2)=4x

The zeros of factor (x+4)(x-2)=4x are x=-2,x=4

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(x + 4) (x - 2) = 4 x

x = - 2, x = 4

Solution steps

(x + 4) (x - 2) = 4 x

Expand

(x + 4) (x - 2) : x^{2} + 2 x - 8

x^{2} + 2 x - 8 = 4 x

Move

4 x

to the left side

x^{2} - 2 x - 8 = 0

Factor

x^{2} - 2 x - 8 : (x + 2) (x - 4)

(x + 2) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x - 4 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 4 = 0 : x = 4

The solutions to the quadratic equation are:

x = - 2, x = 4

x^{2} + 10 x + 23 = - 7

4 x^{2} + 6 x + 1.25 = 0

7 - 8 x - 2 x^{2}

x^{2} - 6 x - 66 = 0

6 x^{(2)} - 3 x = 0

What are the solutions to the equation factor (x+4)(x-2)=4x ?
The solutions to the equation factor (x+4)(x-2)=4x are x=-2,x=4
Find the zeros of factor (x+4)(x-2)=4x
The zeros of factor (x+4)(x-2)=4x are x=-2,x=4