What are the solutions to the equation x^2+10x+23=-7 ?

The solutions to the equation x^2+10x+23=-7 are x=-5+sqrt(5)i,x=-5-sqrt(5)i

Find the zeros of x^2+10x+23=-7

The zeros of x^2+10x+23=-7 are x=-5+sqrt(5)i,x=-5-sqrt(5)i

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x^{2} + 10 x + 23 = - 7

x = - 5 + 5 i, x = - 5 - 5 i

Solution steps

x^{2} + 10 x + 23 = - 7

Move

7

to the left side

x^{2} + 10 x + 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 30}{2 \cdot 1}

Simplify

1 0^{2} - 4 \cdot 1 \cdot 30 : 25 i

x_{1, 2} = \frac{- 10 \pm 2 5 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 5 i}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 5 i}{2 \cdot 1}

x = \frac{- 10 + 2 5 i}{2 \cdot 1} : - 5 + 5 i

x = \frac{- 10 - 2 5 i}{2 \cdot 1} : - 5 - 5 i

The solutions to the quadratic equation are:

x = - 5 + 5 i, x = - 5 - 5 i

4 x^{2} + 6 x + 1.25 = 0

7 - 8 x - 2 x^{2}

x^{2} - 6 x - 66 = 0

6 x^{(2)} - 3 x = 0

28 x^{2} - 21 x = 0

What are the solutions to the equation x^2+10x+23=-7 ?
The solutions to the equation x^2+10x+23=-7 are x=-5+sqrt(5)i,x=-5-sqrt(5)i
Find the zeros of x^2+10x+23=-7
The zeros of x^2+10x+23=-7 are x=-5+sqrt(5)i,x=-5-sqrt(5)i