What are the solutions to the equation 3x^2+9x+12=0 ?

The solutions to the equation 3x^2+9x+12=0 are x=-3/2+i(sqrt(7))/2 ,x=-3/2-i(sqrt(7))/2

Find the zeros of 3x^2+9x+12=0

The zeros of 3x^2+9x+12=0 are x=-3/2+i(sqrt(7))/2 ,x=-3/2-i(sqrt(7))/2

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3 x^{2} + 9 x + 12 = 0

x = - \frac{3}{2} + i \frac{7}{2}, x = - \frac{3}{2} - i \frac{7}{2}

Solution steps

3 x^{2} + 9 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 3 \cdot 12}{2 \cdot 3}

Simplify

9^{2} - 4 \cdot 3 \cdot 12 : 37 i

x_{1, 2} = \frac{- 9 \pm 3 7 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 9 + 3 7 i}{2 \cdot 3}, x_{2} = \frac{- 9 - 3 7 i}{2 \cdot 3}

x = \frac{- 9 + 3 7 i}{2 \cdot 3} : - \frac{3}{2} + i \frac{7}{2}

x = \frac{- 9 - 3 7 i}{2 \cdot 3} : - \frac{3}{2} - i \frac{7}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2} + i \frac{7}{2}, x = - \frac{3}{2} - i \frac{7}{2}

x, x^{2} - x yz = (x - yz)

5 y^{2} - 2 = - 9 y

4 y^{2} + 9 = - 12 y

2 - y^{2} = 0

x^{2} - 8 x = - 5

What are the solutions to the equation 3x^2+9x+12=0 ?
The solutions to the equation 3x^2+9x+12=0 are x=-3/2+i(sqrt(7))/2 ,x=-3/2-i(sqrt(7))/2
Find the zeros of 3x^2+9x+12=0
The zeros of 3x^2+9x+12=0 are x=-3/2+i(sqrt(7))/2 ,x=-3/2-i(sqrt(7))/2