What are the solutions to the equation x-x^2=x^2-1 ?

The solutions to the equation x-x^2=x^2-1 are x=-1/2 ,x=1

Find the zeros of x-x^2=x^2-1

The zeros of x-x^2=x^2-1 are x=-1/2 ,x=1

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x - x^{2} = x^{2} - 1

x = - \frac{1}{2}, x = 1

Decimal Notation

x = - 0.5, x = 1

Solution steps

x - x^{2} = x^{2} - 1

Move

1

to the left side

x - x^{2} + 1 = x^{2}

Move

x^{2}

to the left side

- 2 x^{2} + x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 2 ) \cdot 1}{2 ( - 2 )}

1^{2} - 4 (- 2) \cdot 1 = 3

x_{1, 2} = \frac{- 1 \pm 3}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 1 + 3}{2 ( - 2 )}, x_{2} = \frac{- 1 - 3}{2 ( - 2 )}

x = \frac{- 1 + 3}{2 ( - 2 )} : - \frac{1}{2}

x = \frac{- 1 - 3}{2 ( - 2 )} : 1

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = 1

s^{2} + 6 s = 16

2 x^{2} - 5 x + 6 = - 2 x^{2} - x + 30

x^{2} + 16 x + 40 = 0

2 x^{2} = - 6 x

2 x^{2} + 8 x = 0

What are the solutions to the equation x-x^2=x^2-1 ?
The solutions to the equation x-x^2=x^2-1 are x=-1/2 ,x=1
Find the zeros of x-x^2=x^2-1
The zeros of x-x^2=x^2-1 are x=-1/2 ,x=1