What are the solutions to the equation 0=-12x^2+120x ?

The solutions to the equation 0=-12x^2+120x are x=0,x=10

Find the zeros of 0=-12x^2+120x

The zeros of 0=-12x^2+120x are x=0,x=10

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0 = - 12 x^{2} + 120 x

x = 0, x = 10

Solution steps

0 = - 12 x^{2} + 120 x

Switch sides

- 12 x^{2} + 120 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 120 \pm 12 0 ^{2} - 4 ( - 12 ) \cdot 0}{2 ( - 12 )}

12 0^{2} - 4 (- 12) \cdot 0 = 120

x_{1, 2} = \frac{- 120 \pm 120}{2 ( - 12 )}

Separate the solutions

x_{1} = \frac{- 120 + 120}{2 ( - 12 )}, x_{2} = \frac{- 120 - 120}{2 ( - 12 )}

x = \frac{- 120 + 120}{2 ( - 12 )} : 0

x = \frac{- 120 - 120}{2 ( - 12 )} : 10

The solutions to the quadratic equation are:

x = 0, x = 10

(x - 1)^{2} = \frac{2}{3}

2 x^{2} = 250

(x + 4)^{2} - 2 = 34

3 x (2 x + 1) = 3 x - 12

9 k^{2} + 10 = 0

What are the solutions to the equation 0=-12x^2+120x ?
The solutions to the equation 0=-12x^2+120x are x=0,x=10
Find the zeros of 0=-12x^2+120x
The zeros of 0=-12x^2+120x are x=0,x=10