What are the solutions to the equation (x-1)^2= 2/3 ?

The solutions to the equation (x-1)^2= 2/3 are x=sqrt(2/3)+1,x=-sqrt(2/3)+1

Find the zeros of (x-1)^2= 2/3

The zeros of (x-1)^2= 2/3 are x=sqrt(2/3)+1,x=-sqrt(2/3)+1

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(x - 1)^{2} = \frac{2}{3}

x = \frac{2}{3} + 1, x = - \frac{2}{3} + 1

Decimal Notation

x = 1.81649 \dots, x = 0.18350 \dots

Solution steps

(x - 1)^{2} = \frac{2}{3}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = \frac{2}{3} : x = \frac{2}{3} + 1

Solve

x - 1 = - \frac{2}{3} : x = - \frac{2}{3} + 1

The solutions to the quadratic equation are:

x = \frac{2}{3} + 1, x = - \frac{2}{3} + 1

2 x^{2} = 250

(x + 4)^{2} - 2 = 34

3 x (2 x + 1) = 3 x - 12

9 k^{2} + 10 = 0

7 y^{2} - y + 2 = 0

What are the solutions to the equation (x-1)^2= 2/3 ?
The solutions to the equation (x-1)^2= 2/3 are x=sqrt(2/3)+1,x=-sqrt(2/3)+1
Find the zeros of (x-1)^2= 2/3
The zeros of (x-1)^2= 2/3 are x=sqrt(2/3)+1,x=-sqrt(2/3)+1