What are the solutions to the equation 7y^2-y+2=0 ?

The solutions to the equation 7y^2-y+2=0 are y= 1/14+i(sqrt(55))/(14),y= 1/14-i(sqrt(55))/(14)

Find the zeros of 7y^2-y+2=0

The zeros of 7y^2-y+2=0 are y= 1/14+i(sqrt(55))/(14),y= 1/14-i(sqrt(55))/(14)

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7 y^{2} - y + 2 = 0

y = \frac{1}{14} + i \frac{55}{14}, y = \frac{1}{14} - i \frac{55}{14}

Solution steps

7 y^{2} - y + 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 7 \cdot 2}{2 \cdot 7}

Simplify

(- 1)^{2} - 4 \cdot 7 \cdot 2 : 55 i

y_{1, 2} = \frac{- ( - 1 ) \pm 55 i}{2 \cdot 7}

Separate the solutions

y_{1} = \frac{- ( - 1 ) + 55 i}{2 \cdot 7}, y_{2} = \frac{- ( - 1 ) - 55 i}{2 \cdot 7}

y = \frac{- ( - 1 ) + 55 i}{2 \cdot 7} : \frac{1}{14} + i \frac{55}{14}

y = \frac{- ( - 1 ) - 55 i}{2 \cdot 7} : \frac{1}{14} - i \frac{55}{14}

The solutions to the quadratic equation are:

y = \frac{1}{14} + i \frac{55}{14}, y = \frac{1}{14} - i \frac{55}{14}

3 x^{2} + 4 = 19

2 x^{2} - 8 x + 2

(3 x - 2) (x + 3) = - 6 x - 4

- 1 x^{2} = 8 x^{2} - 5

9 y^{2} - 144 = 0

What are the solutions to the equation 7y^2-y+2=0 ?
The solutions to the equation 7y^2-y+2=0 are y= 1/14+i(sqrt(55))/(14),y= 1/14-i(sqrt(55))/(14)
Find the zeros of 7y^2-y+2=0
The zeros of 7y^2-y+2=0 are y= 1/14+i(sqrt(55))/(14),y= 1/14-i(sqrt(55))/(14)