What are the solutions to the equation w^2-2w+1=0 ?

The solutions to the equation w^2-2w+1=0 are w=1

Find the zeros of w^2-2w+1=0

The zeros of w^2-2w+1=0 are w=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

w^{2} - 2 w + 1 = 0

w = 1

Solution steps

w^{2} - 2 w + 1 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot 1 = 0

w_{1, 2} = \frac{- ( - 2 ) \pm 0}{2 \cdot 1}

w = \frac{- ( - 2 )}{2 \cdot 1}

\frac{- ( - 2 )}{2 \cdot 1} = 1

w = 1

The solution to the quadratic equation is:

w = 1

- 12 u^{2} - 39 = 0

z^{2} + 11 z + 24

4.9 t^{2} + 3.42 t - 5 = 0

2 x^{2} + 4 x - 12 = 0

k = ln (9)

What are the solutions to the equation w^2-2w+1=0 ?
The solutions to the equation w^2-2w+1=0 are w=1
Find the zeros of w^2-2w+1=0
The zeros of w^2-2w+1=0 are w=1