What are the solutions to the equation -12u^2-39=0 ?

The solutions to the equation -12u^2-39=0 are u=(sqrt(13))/2 i,u=-(sqrt(13))/2 i

Find the zeros of -12u^2-39=0

The zeros of -12u^2-39=0 are u=(sqrt(13))/2 i,u=-(sqrt(13))/2 i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 12 u^{2} - 39 = 0

u = \frac{13}{2} i, u = - \frac{13}{2} i

Solution steps

- 12 u^{2} - 39 = 0

Move

39

to the right side

- 12 u^{2} = 39

Divide both sides by

- 12

u^{2} = - \frac{13}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

u = - \frac{13}{4}, u = - - \frac{13}{4}

- \frac{13}{4} = \frac{13}{2} i

- - \frac{13}{4} = - \frac{13}{2} i

u = \frac{13}{2} i, u = - \frac{13}{2} i

z^{2} + 11 z + 24

4.9 t^{2} + 3.42 t - 5 = 0

2 x^{2} + 4 x - 12 = 0

k = ln (9)

u^{2} + 2 u - 1 = 0

What are the solutions to the equation -12u^2-39=0 ?
The solutions to the equation -12u^2-39=0 are u=(sqrt(13))/2 i,u=-(sqrt(13))/2 i
Find the zeros of -12u^2-39=0
The zeros of -12u^2-39=0 are u=(sqrt(13))/2 i,u=-(sqrt(13))/2 i