What are the solutions to the equation (x^2-2x+3)=0 ?

The solutions to the equation (x^2-2x+3)=0 are x=1+sqrt(2)i,x=1-sqrt(2)i

Find the zeros of (x^2-2x+3)=0

The zeros of (x^2-2x+3)=0 are x=1+sqrt(2)i,x=1-sqrt(2)i

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(x^{2} - 2 x + 3) = 0

x = 1 + 2 i, x = 1 - 2 i

Solution steps

(x^{2} - 2 x + 3) = 0

Refine

x^{2} - 2 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 3 : 22 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 2 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 2 i}{2 \cdot 1} : 1 + 2 i

x = \frac{- ( - 2 ) - 2 2 i}{2 \cdot 1} : 1 - 2 i

The solutions to the quadratic equation are:

x = 1 + 2 i, x = 1 - 2 i

- x^{2} + 4 x - 2 = 0

105 = x^{2} + 8 x

0 = 3 x^{2} - 9 x + 27

(x + 17)^{2} = - 36

(y + 2) (y - 1) = 3 y

What are the solutions to the equation (x^2-2x+3)=0 ?
The solutions to the equation (x^2-2x+3)=0 are x=1+sqrt(2)i,x=1-sqrt(2)i
Find the zeros of (x^2-2x+3)=0
The zeros of (x^2-2x+3)=0 are x=1+sqrt(2)i,x=1-sqrt(2)i