What are the solutions to the equation 105=x^2+8x ?

The solutions to the equation 105=x^2+8x are x=7,x=-15

Find the zeros of 105=x^2+8x

The zeros of 105=x^2+8x are x=7,x=-15

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105 = x^{2} + 8 x

x = 7, x = - 15

Solution steps

105 = x^{2} + 8 x

Switch sides

x^{2} + 8 x = 105

Move

105

to the left side

x^{2} + 8 x - 105 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 105 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 105) = 22

x_{1, 2} = \frac{- 8 \pm 22}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 22}{2 \cdot 1}, x_{2} = \frac{- 8 - 22}{2 \cdot 1}

x = \frac{- 8 + 22}{2 \cdot 1} : 7

x = \frac{- 8 - 22}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = 7, x = - 15

0 = 3 x^{2} - 9 x + 27

(x + 17)^{2} = - 36

(y + 2) (y - 1) = 3 y

mn x^{2} + mn = x (m^{2} + n^{2})

x^{2} - 26 x + 153 = 0

What are the solutions to the equation 105=x^2+8x ?
The solutions to the equation 105=x^2+8x are x=7,x=-15
Find the zeros of 105=x^2+8x
The zeros of 105=x^2+8x are x=7,x=-15