What are the solutions to the equation x^2-26x+153=0 ?

The solutions to the equation x^2-26x+153=0 are x=17,x=9

Find the zeros of x^2-26x+153=0

The zeros of x^2-26x+153=0 are x=17,x=9

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x^{2} - 26 x + 153 = 0

x = 17, x = 9

Solution steps

x^{2} - 26 x + 153 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 1 \cdot 153}{2 \cdot 1}

(- 26)^{2} - 4 \cdot 1 \cdot 153 = 8

x_{1, 2} = \frac{- ( - 26 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 26 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 26 ) - 8}{2 \cdot 1}

x = \frac{- ( - 26 ) + 8}{2 \cdot 1} : 17

x = \frac{- ( - 26 ) - 8}{2 \cdot 1} : 9

The solutions to the quadratic equation are:

x = 17, x = 9

x^{2} - 5 x = 104

(z + 1)^{3} = z^{3}

6 x^{2} - 19 - 2 x = - 3 - 2 x + 5 x^{2}

\frac{b - 2 x ^{2}}{a} = m

(x + 9) + (x + 9)^{2} = 0

What are the solutions to the equation x^2-26x+153=0 ?
The solutions to the equation x^2-26x+153=0 are x=17,x=9
Find the zeros of x^2-26x+153=0
The zeros of x^2-26x+153=0 are x=17,x=9