What are the solutions to the equation u^2+2u-1=0 ?

The solutions to the equation u^2+2u-1=0 are u=-1+sqrt(2),u=-1-sqrt(2)

Find the zeros of u^2+2u-1=0

The zeros of u^2+2u-1=0 are u=-1+sqrt(2),u=-1-sqrt(2)

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u^{2} + 2 u - 1 = 0

u = - 1 + 2, u = - 1 - 2

Decimal Notation

u = 0.41421 \dots, u = - 2.41421 \dots

Solution steps

u^{2} + 2 u - 1 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 1) = 22

u_{1, 2} = \frac{- 2 \pm 2 2}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 2 + 2 2}{2 \cdot 1}, u_{2} = \frac{- 2 - 2 2}{2 \cdot 1}

u = \frac{- 2 + 2 2}{2 \cdot 1} : - 1 + 2

u = \frac{- 2 - 2 2}{2 \cdot 1} : - 1 - 2

The solutions to the quadratic equation are:

u = - 1 + 2, u = - 1 - 2

2 x^{2} \cdot 2 x

8 x - 7 = x + 14

- 5 - 7 x < - 40

\frac{2 x ^{4} y ^{- 4} z ^{- 3}}{3 x ^{2} y ^{- 3} z ^{4}}

\frac{49}{4}

What are the solutions to the equation u^2+2u-1=0 ?
The solutions to the equation u^2+2u-1=0 are u=-1+sqrt(2),u=-1-sqrt(2)
Find the zeros of u^2+2u-1=0
The zeros of u^2+2u-1=0 are u=-1+sqrt(2),u=-1-sqrt(2)