What are the solutions to the equation x^2-7x-330=0 ?

The solutions to the equation x^2-7x-330=0 are x=22,x=-15

Find the zeros of x^2-7x-330=0

The zeros of x^2-7x-330=0 are x=22,x=-15

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x^{2} - 7 x - 330 = 0

x = 22, x = - 15

Solution steps

x^{2} - 7 x - 330 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 330 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 330) = 37

x_{1, 2} = \frac{- ( - 7 ) \pm 37}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 37}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 37}{2 \cdot 1}

x = \frac{- ( - 7 ) + 37}{2 \cdot 1} : 22

x = \frac{- ( - 7 ) - 37}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = 22, x = - 15

x, 0 = 4 x^{2} + y^{2}

x^{2} - 12 x = - 31

s^{2} + 2 s + 1.49

3 x^{2} + 39 = 0

- m^{2} + 2 m = - 35

What are the solutions to the equation x^2-7x-330=0 ?
The solutions to the equation x^2-7x-330=0 are x=22,x=-15
Find the zeros of x^2-7x-330=0
The zeros of x^2-7x-330=0 are x=22,x=-15