What are the solutions to the equation x^2-12x=-31 ?

The solutions to the equation x^2-12x=-31 are x=6+sqrt(5),x=6-sqrt(5)

Find the zeros of x^2-12x=-31

The zeros of x^2-12x=-31 are x=6+sqrt(5),x=6-sqrt(5)

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x^{2} - 12 x = - 31

x = 6 + 5, x = 6 - 5

Decimal Notation

x = 8.23606 \dots, x = 3.76393 \dots

Solution steps

x^{2} - 12 x = - 31

Move

31

to the left side

x^{2} - 12 x + 31 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 31}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 31 = 25

x_{1, 2} = \frac{- ( - 12 ) \pm 2 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 5}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2 5}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2 5}{2 \cdot 1} : 6 + 5

x = \frac{- ( - 12 ) - 2 5}{2 \cdot 1} : 6 - 5

The solutions to the quadratic equation are:

x = 6 + 5, x = 6 - 5

s^{2} + 2 s + 1.49

3 x^{2} + 39 = 0

- m^{2} + 2 m = - 35

t^{2} + 9 t + 3 = - 4 t^{2}

- 2 x^{2} + 36 x = 157

What are the solutions to the equation x^2-12x=-31 ?
The solutions to the equation x^2-12x=-31 are x=6+sqrt(5),x=6-sqrt(5)
Find the zeros of x^2-12x=-31
The zeros of x^2-12x=-31 are x=6+sqrt(5),x=6-sqrt(5)