What are the solutions to the equation p^2+16p-4=0 ?

The solutions to the equation p^2+16p-4=0 are p=2(sqrt(17)-4),p=-2(4+sqrt(17))

Find the zeros of p^2+16p-4=0

The zeros of p^2+16p-4=0 are p=2(sqrt(17)-4),p=-2(4+sqrt(17))

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p^{2} + 16 p - 4 = 0

p = 2 (17 - 4), p = - 2 (4 + 17)

Decimal Notation

p = 0.24621 \dots, p = - 16.24621 \dots

Solution steps

p^{2} + 16 p - 4 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot (- 4) = 417

p_{1, 2} = \frac{- 16 \pm 4 17}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 16 + 4 17}{2 \cdot 1}, p_{2} = \frac{- 16 - 4 17}{2 \cdot 1}

p = \frac{- 16 + 4 17}{2 \cdot 1} : 2 (17 - 4)

p = \frac{- 16 - 4 17}{2 \cdot 1} : - 2 (4 + 17)

The solutions to the quadratic equation are:

p = 2 (17 - 4), p = - 2 (4 + 17)

3 m^{2} - 4 m + 4 = 5

5 x^{2} + 50 x - 195 = 0

4 x^{2} - 22 x + 10 = 0

10000 = 800 p - 7 p^{2}

5 x^{2} + 8 x - 13 = 0

What are the solutions to the equation p^2+16p-4=0 ?
The solutions to the equation p^2+16p-4=0 are p=2(sqrt(17)-4),p=-2(4+sqrt(17))
Find the zeros of p^2+16p-4=0
The zeros of p^2+16p-4=0 are p=2(sqrt(17)-4),p=-2(4+sqrt(17))