What are the solutions to the equation 5x^2-4x+1/5 =0 ?

The solutions to the equation 5x^2-4x+1/5 =0 are x=(2+sqrt(3))/5 ,x=(2-sqrt(3))/5

Find the zeros of 5x^2-4x+1/5 =0

The zeros of 5x^2-4x+1/5 =0 are x=(2+sqrt(3))/5 ,x=(2-sqrt(3))/5

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5 x^{2} - 4 x + \frac{1}{5} = 0

x = \frac{2 + 3}{5}, x = \frac{2 - 3}{5}

Decimal Notation

x = 0.74641 \dots, x = 0.05358 \dots

Solution steps

5 x^{2} - 4 x + \frac{1}{5} = 0

Multiply both sides by

5

25 x^{2} - 20 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 25 \cdot 1}{2 \cdot 25}

(- 20)^{2} - 4 \cdot 25 \cdot 1 = 103

x_{1, 2} = \frac{- ( - 20 ) \pm 10 3}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 10 3}{2 \cdot 25}, x_{2} = \frac{- ( - 20 ) - 10 3}{2 \cdot 25}

x = \frac{- ( - 20 ) + 10 3}{2 \cdot 25} : \frac{2 + 3}{5}

x = \frac{- ( - 20 ) - 10 3}{2 \cdot 25} : \frac{2 - 3}{5}

The solutions to the quadratic equation are:

x = \frac{2 + 3}{5}, x = \frac{2 - 3}{5}

x, x^{2} - x - 20 = 0

4 x^{2} - 4 x + 6 = 0

x^{2} - \frac{1}{144} = 0

(y - 3)^{2} = 5

- 4 = 2 (x - 3)^{2} - 6

What are the solutions to the equation 5x^2-4x+1/5 =0 ?
The solutions to the equation 5x^2-4x+1/5 =0 are x=(2+sqrt(3))/5 ,x=(2-sqrt(3))/5
Find the zeros of 5x^2-4x+1/5 =0
The zeros of 5x^2-4x+1/5 =0 are x=(2+sqrt(3))/5 ,x=(2-sqrt(3))/5