What are the solutions to the equation -4=2(x-3)^2-6 ?

The solutions to the equation -4=2(x-3)^2-6 are x=4,x=2

Find the zeros of -4=2(x-3)^2-6

The zeros of -4=2(x-3)^2-6 are x=4,x=2

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- 4 = 2 (x - 3)^{2} - 6

x = 4, x = 2

Solution steps

- 4 = 2 (x - 3)^{2} - 6

Switch sides

2 (x - 3)^{2} - 6 = - 4

Move

6

to the right side

2 (x - 3)^{2} = 2

Divide both sides by

2

(x - 3)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 1 : x = 4

Solve

x - 3 = - 1 : x = 2

The solutions to the quadratic equation are:

x = 4, x = 2

4 (x^{2} - 5) - 1 = 33

- 3 x (x - 1) = 8 (3 + x)

4.5 x^{2} = 2.5 (x + 0.5)^{2}

x^{2} + 27 = 12 x

x, x^{2} + x y - y^{2} = - 5

What are the solutions to the equation -4=2(x-3)^2-6 ?
The solutions to the equation -4=2(x-3)^2-6 are x=4,x=2
Find the zeros of -4=2(x-3)^2-6
The zeros of -4=2(x-3)^2-6 are x=4,x=2