What are the solutions to the equation 9x^2+27x+20=0 ?

The solutions to the equation 9x^2+27x+20=0 are x=-4/3 ,x=-5/3

Find the zeros of 9x^2+27x+20=0

The zeros of 9x^2+27x+20=0 are x=-4/3 ,x=-5/3

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9 x^{2} + 27 x + 20 = 0

x = - \frac{4}{3}, x = - \frac{5}{3}

Decimal Notation

x = - 1.33333 \dots, x = - 1.66666 \dots

Solution steps

9 x^{2} + 27 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 27 \pm 2 7 ^{2} - 4 \cdot 9 \cdot 20}{2 \cdot 9}

2 7^{2} - 4 \cdot 9 \cdot 20 = 3

x_{1, 2} = \frac{- 27 \pm 3}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 27 + 3}{2 \cdot 9}, x_{2} = \frac{- 27 - 3}{2 \cdot 9}

x = \frac{- 27 + 3}{2 \cdot 9} : - \frac{4}{3}

x = \frac{- 27 - 3}{2 \cdot 9} : - \frac{5}{3}

The solutions to the quadratic equation are:

x = - \frac{4}{3}, x = - \frac{5}{3}

x^{2} - 105 x - 5040 = 0

4 x^{2} - 2 x - 16 = 0

(2 x + 9)^{2} = 64

5 y^{2} = 405

\frac{1}{4} x \frac{1}{2} x = 9

What are the solutions to the equation 9x^2+27x+20=0 ?
The solutions to the equation 9x^2+27x+20=0 are x=-4/3 ,x=-5/3
Find the zeros of 9x^2+27x+20=0
The zeros of 9x^2+27x+20=0 are x=-4/3 ,x=-5/3