What are the solutions to the equation 5y^2+26y=-5 ?

The solutions to the equation 5y^2+26y=-5 are y=-1/5 ,y=-5

Find the zeros of 5y^2+26y=-5

The zeros of 5y^2+26y=-5 are y=-1/5 ,y=-5

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5 y^{2} + 26 y = - 5

y = - \frac{1}{5}, y = - 5

Decimal Notation

y = - 0.2, y = - 5

Solution steps

5 y^{2} + 26 y = - 5

Move

5

to the left side

5 y^{2} + 26 y + 5 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 26 \pm 2 6 ^{2} - 4 \cdot 5 \cdot 5}{2 \cdot 5}

2 6^{2} - 4 \cdot 5 \cdot 5 = 24

y_{1, 2} = \frac{- 26 \pm 24}{2 \cdot 5}

Separate the solutions

y_{1} = \frac{- 26 + 24}{2 \cdot 5}, y_{2} = \frac{- 26 - 24}{2 \cdot 5}

y = \frac{- 26 + 24}{2 \cdot 5} : - \frac{1}{5}

y = \frac{- 26 - 24}{2 \cdot 5} : - 5

The solutions to the quadratic equation are:

y = - \frac{1}{5}, y = - 5

x^{2} + 28 x + 196 = 0

(x + 4)^{2} - 5 = 31

x^{2} + 4 x - 8 = 0

4 x^{2} + 16 x

m, F = \frac{g mm}{d ^{2}}

What are the solutions to the equation 5y^2+26y=-5 ?
The solutions to the equation 5y^2+26y=-5 are y=-1/5 ,y=-5
Find the zeros of 5y^2+26y=-5
The zeros of 5y^2+26y=-5 are y=-1/5 ,y=-5