What are the solutions to the equation 22=-2-3/4 (x-2)^2 ?

The solutions to the equation 22=-2-3/4 (x-2)^2 are x=4sqrt(2)i+2,x=-4sqrt(2)i+2

Find the zeros of 22=-2-3/4 (x-2)^2

The zeros of 22=-2-3/4 (x-2)^2 are x=4sqrt(2)i+2,x=-4sqrt(2)i+2

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22 = - 2 - \frac{3}{4} (x - 2)^{2}

x = 42 i + 2, x = - 42 i + 2

Solution steps

22 = - 2 - \frac{3}{4} (x - 2)^{2}

Switch sides

- 2 - \frac{3}{4} (x - 2)^{2} = 22

Move

2

to the right side

- \frac{3}{4} (x - 2)^{2} = 24

Multiply both sides by

4

- 3 (x - 2)^{2} = 96

Divide both sides by

- 3

(x - 2)^{2} = - 32

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = - 32 : x = 42 i + 2

Solve

x - 2 = - - 32 : x = - 42 i + 2

The solutions to the quadratic equation are:

x = 42 i + 2, x = - 42 i + 2

(2 x - 3)^{2} + 3 (x + 4) = 5

2 m^{2} + 10 m + 3 = 0

- 4.9 x^{2} + 2 x + 10 = 0

- 5 x^{2} - 5 x = 0

x^{2} - 8 x + 9 = 56

What are the solutions to the equation 22=-2-3/4 (x-2)^2 ?
The solutions to the equation 22=-2-3/4 (x-2)^2 are x=4sqrt(2)i+2,x=-4sqrt(2)i+2
Find the zeros of 22=-2-3/4 (x-2)^2
The zeros of 22=-2-3/4 (x-2)^2 are x=4sqrt(2)i+2,x=-4sqrt(2)i+2