What are the solutions to the equation -4.9x^2+2x+10=0 ?

The solutions to the equation -4.9x^2+2x+10=0 are x=-(10(5sqrt(2)-1))/(49),x=(10(1+5sqrt(2)))/(49)

Find the zeros of -4.9x^2+2x+10=0

The zeros of -4.9x^2+2x+10=0 are x=-(10(5sqrt(2)-1))/(49),x=(10(1+5sqrt(2)))/(49)

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- 4.9 x^{2} + 2 x + 10 = 0

x = - \frac{10 ( 5 2 - 1 )}{49}, x = \frac{10 ( 1 + 5 2 )}{49}

Decimal Notation

x = - 1.23899 \dots, x = 1.64715 \dots

Solution steps

- 4.9 x^{2} + 2 x + 10 = 0

Multiply both sides by

10

- 49 x^{2} + 20 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 ( - 49 ) \cdot 100}{2 ( - 49 )}

2 0^{2} - 4 (- 49) \cdot 100 = 1002

x_{1, 2} = \frac{- 20 \pm 100 2}{2 ( - 49 )}

Separate the solutions

x_{1} = \frac{- 20 + 100 2}{2 ( - 49 )}, x_{2} = \frac{- 20 - 100 2}{2 ( - 49 )}

x = \frac{- 20 + 100 2}{2 ( - 49 )} : - \frac{10 ( 5 2 - 1 )}{49}

x = \frac{- 20 - 100 2}{2 ( - 49 )} : \frac{10 ( 1 + 5 2 )}{49}

The solutions to the quadratic equation are:

x = - \frac{10 ( 5 2 - 1 )}{49}, x = \frac{10 ( 1 + 5 2 )}{49}

- 5 x^{2} - 5 x = 0

x^{2} - 8 x + 9 = 56

x, (x + y) (x + y) = 1

x^{2} - 2 x - 35 = 0

3 h^{2} = 147

What are the solutions to the equation -4.9x^2+2x+10=0 ?
The solutions to the equation -4.9x^2+2x+10=0 are x=-(10(5sqrt(2)-1))/(49),x=(10(1+5sqrt(2)))/(49)
Find the zeros of -4.9x^2+2x+10=0
The zeros of -4.9x^2+2x+10=0 are x=-(10(5sqrt(2)-1))/(49),x=(10(1+5sqrt(2)))/(49)