What are the solutions to the equation 10x^2-12x=15 ?

The solutions to the equation 10x^2-12x=15 are x=(6+sqrt(186))/(10),x=(6-sqrt(186))/(10)

Find the zeros of 10x^2-12x=15

The zeros of 10x^2-12x=15 are x=(6+sqrt(186))/(10),x=(6-sqrt(186))/(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

10 x^{2} - 12 x = 15

x = \frac{6 + 186}{10}, x = \frac{6 - 186}{10}

Decimal Notation

x = 1.96381 \dots, x = - 0.76381 \dots

Solution steps

10 x^{2} - 12 x = 15

Move

15

to the left side

10 x^{2} - 12 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 10 ( - 15 )}{2 \cdot 10}

(- 12)^{2} - 4 \cdot 10 (- 15) = 2186

x_{1, 2} = \frac{- ( - 12 ) \pm 2 186}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 186}{2 \cdot 10}, x_{2} = \frac{- ( - 12 ) - 2 186}{2 \cdot 10}

x = \frac{- ( - 12 ) + 2 186}{2 \cdot 10} : \frac{6 + 186}{10}

x = \frac{- ( - 12 ) - 2 186}{2 \cdot 10} : \frac{6 - 186}{10}

The solutions to the quadratic equation are:

x = \frac{6 + 186}{10}, x = \frac{6 - 186}{10}

7 - 3 x^{2} = 0

10 x^{2} - 13 x + 4 = 0

4 x^{2} = 2 - 6 x

(5 x - 4)^{2} = 16

(2 x + 2)^{2} = 16

What are the solutions to the equation 10x^2-12x=15 ?
The solutions to the equation 10x^2-12x=15 are x=(6+sqrt(186))/(10),x=(6-sqrt(186))/(10)
Find the zeros of 10x^2-12x=15
The zeros of 10x^2-12x=15 are x=(6+sqrt(186))/(10),x=(6-sqrt(186))/(10)