What are the solutions to the equation 1/3 (x+4)^2-1=5 ?

The solutions to the equation 1/3 (x+4)^2-1=5 are x=3sqrt(2)-4,x=-3sqrt(2)-4

Find the zeros of 1/3 (x+4)^2-1=5

The zeros of 1/3 (x+4)^2-1=5 are x=3sqrt(2)-4,x=-3sqrt(2)-4

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\frac{1}{3} (x + 4)^{2} - 1 = 5

x = 32 - 4, x = - 32 - 4

Decimal Notation

x = 0.24264 \dots, x = - 8.24264 \dots

Solution steps

\frac{1}{3} (x + 4)^{2} - 1 = 5

Move

1

to the right side

\frac{1}{3} (x + 4)^{2} = 6

Multiply both sides by

3

(x + 4)^{2} = 18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 18 : x = 32 - 4

Solve

x + 4 = - 18 : x = - 32 - 4

The solutions to the quadratic equation are:

x = 32 - 4, x = - 32 - 4

- 2 x^{2} - 3 x + 9 = 0

x^{2} + 7 = 2 x

5 b^{2} - 36 b = 32

(2 y - 1)^{2} - (2 y - 1) y + y^{2} - 7 = 0

x^{2} + a x - 8 = 0

What are the solutions to the equation 1/3 (x+4)^2-1=5 ?
The solutions to the equation 1/3 (x+4)^2-1=5 are x=3sqrt(2)-4,x=-3sqrt(2)-4
Find the zeros of 1/3 (x+4)^2-1=5
The zeros of 1/3 (x+4)^2-1=5 are x=3sqrt(2)-4,x=-3sqrt(2)-4