What are the solutions to the equation -4x^2+800x-30000=0 ?

The solutions to the equation -4x^2+800x-30000=0 are x=50,x=150

Find the zeros of -4x^2+800x-30000=0

The zeros of -4x^2+800x-30000=0 are x=50,x=150

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- 4 x^{2} + 800 x - 30000 = 0

x = 50, x = 150

Solution steps

- 4 x^{2} + 800 x - 30000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 800 \pm 80 0 ^{2} - 4 ( - 4 ) ( - 30000 )}{2 ( - 4 )}

80 0^{2} - 4 (- 4) (- 30000) = 400

x_{1, 2} = \frac{- 800 \pm 400}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 800 + 400}{2 ( - 4 )}, x_{2} = \frac{- 800 - 400}{2 ( - 4 )}

x = \frac{- 800 + 400}{2 ( - 4 )} : 50

x = \frac{- 800 - 400}{2 ( - 4 )} : 150

The solutions to the quadratic equation are:

x = 50, x = 150

x^{2} + (- 1)^{2} + 2 x + 4 (- 1) + 2 = 0

9 x^{2} = 121

9 x^{2} = 18 x

h^{2} + 2 h - 5 = 0

x, x^{2} - x - 56 = 0

What are the solutions to the equation -4x^2+800x-30000=0 ?
The solutions to the equation -4x^2+800x-30000=0 are x=50,x=150
Find the zeros of -4x^2+800x-30000=0
The zeros of -4x^2+800x-30000=0 are x=50,x=150