What are the solutions to the equation 4.9t^2-70t+50=0 ?

The solutions to the equation 4.9t^2-70t+50=0 are t=(10(5+2sqrt(5)))/7 ,t=(10(5-2sqrt(5)))/7

Find the zeros of 4.9t^2-70t+50=0

The zeros of 4.9t^2-70t+50=0 are t=(10(5+2sqrt(5)))/7 ,t=(10(5-2sqrt(5)))/7

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4.9 t^{2} - 70 t + 50 = 0

t = \frac{10 ( 5 + 2 5 )}{7}, t = \frac{10 ( 5 - 2 5 )}{7}

Decimal Notation

t = 13.53162 \dots, t = 0.75409 \dots

Solution steps

4.9 t^{2} - 70 t + 50 = 0

Multiply both sides by

10

49 t^{2} - 700 t + 500 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 700 ) \pm ( - 700 ) ^{2} - 4 \cdot 49 \cdot 500}{2 \cdot 49}

(- 700)^{2} - 4 \cdot 49 \cdot 500 = 2805

t_{1, 2} = \frac{- ( - 700 ) \pm 280 5}{2 \cdot 49}

Separate the solutions

t_{1} = \frac{- ( - 700 ) + 280 5}{2 \cdot 49}, t_{2} = \frac{- ( - 700 ) - 280 5}{2 \cdot 49}

t = \frac{- ( - 700 ) + 280 5}{2 \cdot 49} : \frac{10 ( 5 + 2 5 )}{7}

t = \frac{- ( - 700 ) - 280 5}{2 \cdot 49} : \frac{10 ( 5 - 2 5 )}{7}

The solutions to the quadratic equation are:

t = \frac{10 ( 5 + 2 5 )}{7}, t = \frac{10 ( 5 - 2 5 )}{7}

x^{2} + 4 = 10 x

1800 = \frac{1}{2} (5) t^{2}

x^{2} - 5 x - 9 = 0

1 + x - 2 x^{2} = 0

- x^{2} + 155 x - 2800 = 0

What are the solutions to the equation 4.9t^2-70t+50=0 ?
The solutions to the equation 4.9t^2-70t+50=0 are t=(10(5+2sqrt(5)))/7 ,t=(10(5-2sqrt(5)))/7
Find the zeros of 4.9t^2-70t+50=0
The zeros of 4.9t^2-70t+50=0 are t=(10(5+2sqrt(5)))/7 ,t=(10(5-2sqrt(5)))/7