What are the solutions to the equation (13x-1)^2-2(13x-1)-3=0 ?

The solutions to the equation (13x-1)^2-2(13x-1)-3=0 are x= 4/13 ,x=0

Find the zeros of (13x-1)^2-2(13x-1)-3=0

The zeros of (13x-1)^2-2(13x-1)-3=0 are x= 4/13 ,x=0

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(13 x - 1)^{2} - 2 (13 x - 1) - 3 = 0

x = \frac{4}{13}, x = 0

Decimal Notation

x = 0.30769 \dots, x = 0

Solution steps

(13 x - 1)^{2} - 2 (13 x - 1) - 3 = 0

Expand

(13 x - 1)^{2} - 2 (13 x - 1) - 3 : 169 x^{2} - 52 x

169 x^{2} - 52 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 52 ) \pm ( - 52 ) ^{2} - 4 \cdot 169 \cdot 0}{2 \cdot 169}

(- 52)^{2} - 4 \cdot 169 \cdot 0 = 52

x_{1, 2} = \frac{- ( - 52 ) \pm 52}{2 \cdot 169}

Separate the solutions

x_{1} = \frac{- ( - 52 ) + 52}{2 \cdot 169}, x_{2} = \frac{- ( - 52 ) - 52}{2 \cdot 169}

x = \frac{- ( - 52 ) + 52}{2 \cdot 169} : \frac{4}{13}

x = \frac{- ( - 52 ) - 52}{2 \cdot 169} : 0

The solutions to the quadratic equation are:

x = \frac{4}{13}, x = 0

4 = x^{2} - 7 x + 10

a + 6 = a^{2}

2 x + 6 - \frac{x ^{2} + 1}{2} = 4 - x^{2}

4 x^{2} = - 15

x^{2} + (x - 4)^{2} = 20

What are the solutions to the equation (13x-1)^2-2(13x-1)-3=0 ?
The solutions to the equation (13x-1)^2-2(13x-1)-3=0 are x= 4/13 ,x=0
Find the zeros of (13x-1)^2-2(13x-1)-3=0
The zeros of (13x-1)^2-2(13x-1)-3=0 are x= 4/13 ,x=0