What are the solutions to the equation 4x^2=-15 ?

The solutions to the equation 4x^2=-15 are x=(sqrt(15))/2 i,x=-(sqrt(15))/2 i

Find the zeros of 4x^2=-15

The zeros of 4x^2=-15 are x=(sqrt(15))/2 i,x=-(sqrt(15))/2 i

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4 x^{2} = - 15

x = \frac{15}{2} i, x = - \frac{15}{2} i

Solution steps

4 x^{2} = - 15

Divide both sides by

4

x^{2} = - \frac{15}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{15}{4}, x = - - \frac{15}{4}

- \frac{15}{4} = \frac{15}{2} i

- - \frac{15}{4} = - \frac{15}{2} i

x = \frac{15}{2} i, x = - \frac{15}{2} i

x^{2} + (x - 4)^{2} = 20

a x^{2} + 2 x + c = 2

3 x^{2} - 14 x = x^{2} + 12

- 5 + 16 x^{2} = 95

(4 x - 1)^{2} = 16

What are the solutions to the equation 4x^2=-15 ?
The solutions to the equation 4x^2=-15 are x=(sqrt(15))/2 i,x=-(sqrt(15))/2 i
Find the zeros of 4x^2=-15
The zeros of 4x^2=-15 are x=(sqrt(15))/2 i,x=-(sqrt(15))/2 i