What are the solutions to the equation -5+16x^2=95 ?

The solutions to the equation -5+16x^2=95 are x= 5/2 ,x=-5/2

Find the zeros of -5+16x^2=95

The zeros of -5+16x^2=95 are x= 5/2 ,x=-5/2

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- 5 + 16 x^{2} = 95

x = \frac{5}{2}, x = - \frac{5}{2}

Decimal Notation

x = 2.5, x = - 2.5

Solution steps

- 5 + 16 x^{2} = 95

Move

5

to the right side

16 x^{2} = 100

Divide both sides by

16

x^{2} = \frac{25}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{25}{4}, x = - \frac{25}{4}

\frac{25}{4} = \frac{5}{2}

- \frac{25}{4} = - \frac{5}{2}

x = \frac{5}{2}, x = - \frac{5}{2}

(4 x - 1)^{2} = 16

- x^{2} + 12 x - 2 = 0

5.5 t^{2} + 44 t - 160 = 0

2 t^{2} + 8 t + 8 = 0

81 (x - 2)^{2} = 16

What are the solutions to the equation -5+16x^2=95 ?
The solutions to the equation -5+16x^2=95 are x= 5/2 ,x=-5/2
Find the zeros of -5+16x^2=95
The zeros of -5+16x^2=95 are x= 5/2 ,x=-5/2