What are the solutions to the equation 5m^2+4=m ?

The solutions to the equation 5m^2+4=m are m= 1/10+i(sqrt(79))/(10),m= 1/10-i(sqrt(79))/(10)

Find the zeros of 5m^2+4=m

The zeros of 5m^2+4=m are m= 1/10+i(sqrt(79))/(10),m= 1/10-i(sqrt(79))/(10)

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5 m^{2} + 4 = m

m = \frac{1}{10} + i \frac{79}{10}, m = \frac{1}{10} - i \frac{79}{10}

Solution steps

5 m^{2} + 4 = m

Move

m

to the left side

5 m^{2} + 4 - m = 0

Write in the standard form

a x^{2} + b x + c = 0

5 m^{2} - m + 4 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

Simplify

(- 1)^{2} - 4 \cdot 5 \cdot 4 : 79 i

m_{1, 2} = \frac{- ( - 1 ) \pm 79 i}{2 \cdot 5}

Separate the solutions

m_{1} = \frac{- ( - 1 ) + 79 i}{2 \cdot 5}, m_{2} = \frac{- ( - 1 ) - 79 i}{2 \cdot 5}

m = \frac{- ( - 1 ) + 79 i}{2 \cdot 5} : \frac{1}{10} + i \frac{79}{10}

m = \frac{- ( - 1 ) - 79 i}{2 \cdot 5} : \frac{1}{10} - i \frac{79}{10}

The solutions to the quadratic equation are:

m = \frac{1}{10} + i \frac{79}{10}, m = \frac{1}{10} - i \frac{79}{10}

2 w^{2} + 3 w - 54 = 0

x, x^{2} = ln (y) - ln (3)

k^{2} - 5 k = 6

b^{2} = 1 - \frac{1}{9 ^{2}}

- x^{2} + 8 x - 8 = 0

What are the solutions to the equation 5m^2+4=m ?
The solutions to the equation 5m^2+4=m are m= 1/10+i(sqrt(79))/(10),m= 1/10-i(sqrt(79))/(10)
Find the zeros of 5m^2+4=m
The zeros of 5m^2+4=m are m= 1/10+i(sqrt(79))/(10),m= 1/10-i(sqrt(79))/(10)