What are the solutions to the equation k^2-5k=6 ?

The solutions to the equation k^2-5k=6 are k=6,k=-1

Find the zeros of k^2-5k=6

The zeros of k^2-5k=6 are k=6,k=-1

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k^{2} - 5 k = 6

k = 6, k = - 1

Solution steps

k^{2} - 5 k = 6

Move

6

to the left side

k^{2} - 5 k - 6 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 6) = 7

k_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 1}, k_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 1}

k = \frac{- ( - 5 ) + 7}{2 \cdot 1} : 6

k = \frac{- ( - 5 ) - 7}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

k = 6, k = - 1

b^{2} = 1 - \frac{1}{9 ^{2}}

- x^{2} + 8 x - 8 = 0

p^{2} + 10 p + 1 = 0

x^{2} = \frac{5}{2}

2 (3 x - 1)^{2} = 32

What are the solutions to the equation k^2-5k=6 ?
The solutions to the equation k^2-5k=6 are k=6,k=-1
Find the zeros of k^2-5k=6
The zeros of k^2-5k=6 are k=6,k=-1